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Commands that take only one argument the service to check use the check_nrpe_1arg command (see /etc/nagios-plugins/config/check_nrpe.cfg). If you want to give further arguments to commands, you need to edit /etc/nagios/nrpe.cfg on the client machine so that the dont_blame_nrpe keyword has the value 1. Then use the check_nrpe command. In the previous code, I use it to pass the disk mount point to be checked.

All rows occurring in Q1 or in Q2 (or in both) As UNION, retaining duplicate rows The rows from Q1, without the rows from Q2 The rows occurring in Q1 and in Q2

pos.x = (int)(pos.x / tileMap.tileSize.width);

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By default, all three set operators suppress duplicate rows in the query result. The only exception to this rule is the UNION ALL operator, which does not eliminate duplicate rows. One important advantage of the UNION ALL operator is that the Oracle DBMS does not need to sort the rows. Sorting is needed for all other set operators to trace duplicate rows. The UNION, MINUS, and INTERSECT operators cannot be applied to any arbitrary set of two queries. The intermediate (separate) results of queries Q1 and Q2 must be compatible in order to use them as arguments to a set operator. In this context, compatibility means the following: Q1 and Q2 must select the same number of column expressions. The datatypes of those column expressions must match. Some other rules and guidelines for SQL set operators are the following: The result table inherits the column names (or aliases) from Q1. Q1 cannot contain an ORDER BY clause. If you specify an ORDER BY clause at the end of the query, it doesn t refer to Q2, but rather to the total result of the set operator.

The tileMap.tileSize property is the size of the tiles in the tileset, which in this case is 32 32 (see also Figure 10 6). If the touch were at the 340 x position, the calculation would reveal the following:

Note Setting dont_blame_nrpe to 1 is a security hole. The arguments passed to NRPE aren t thoroughly

Set operators are very convenient when building new queries by combining the multiple query blocks you wrote (and tested) before, without writing completely new SQL code. This simplifies testing, because you have more control over correctness. Listing 8-44 answers the following question: Which locations host course offerings without having a department Listing 8-44. MINUS Set Operator Example SQL> select o.location from offerings o 2 MINUS 3 select d.location from departments d; LOCATION -------SEATTLE SQL> You can also try to solve this problem without using the MINUS operator. See Listing 8-45 for a suggestion. Listing 8-45. Alternative Solution Without Using the MINUS Operator SQL> select DISTINCT o.location 2 from offerings o 3 where o.location not in 4 (select d.location 5 from departments d) Note that you must add a DISTINCT operator, to handle situations where you have multiple course offerings in the same location. As explained before, the MINUS operator automatically removes duplicate rows. Are the two queries in Listing 8-44 and 8-45 logically equivalent Further investigations are left to the readers in one of the exercises at the end of this chapter. You can also produce outer join results by using the UNION operator. You will see how to do this in Listings 8-46 and 8-47. We start with a regular join in Listing 8-46. In Listing 8-47 you add the additional department(s) needed for the outer join with a UNION operator, while assigning the right number of employees for those departments: zero. Listing 8-46. Regular Join SQL> 2 3 4 5 6 select , , from , where d.deptno d.dname count(e.empno) as headcount employees e departments d e.deptno = d.deptno

340 / 32 = 10.625

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