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In addition to the sensing of a small bit line signal, another important function of the sense amplifier is writing back the full signal into the memory cell. As indicated in Figure 7.16, the sense amplifier will latch completely after a sufficient time, and the BL and BL approach VDD and 0 V, respectively, for the case of data "high." This condition, however, is not sufficient to write back a full VDD signal to the memory cell capacitor due to the threshold voltage drop through the pass transistor. The word line voltage must be "boosted" above the VDD level in order to write a full VDD signal to the memory cell. This situation is illustrated in Figure 7.17. Since the source of the pass transistor (bit line) is at VDD, the pass transistor sees an effective back bias voltage of -(IVBBI + VDD), where VRR is the normal back bias with the source at ground. For a DRAM chip with VDD = 2.5 V, VRB is usually between - 1 and - 1.5 V. Therefore, the effective back bias that the pass transistor sees can be as large as -4 V. The threshold voltage of the pass transistor with this back bias is much higher than the threshold voltage with normal VRB = -- 1.5 V, and can be around 1.2 Vor higher. The word line voltage VWL must be above the source voltage, which is VDD in this case, by at least this threshold voltage. Therefore, the required

For the autocorrelation sequence of the process z(n) we thus derive r z z ( m ) = E {z*(n)z(n m ) }

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This means that the temporal correlation function (t,r ) is replaced by its expected value, which is the autocorrelation function r z z(t 5, t - 5) of the process z ( t ) .

have large areas of very light tones also need to be overexposed. A scene shot in snow or on a bright sandy beach tends to be underexposed if left up to the camera.

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Rule 1: Never change the output of a given estimating process phase without a corresponding change to the inputs of that phase.

The signal received can also be detected noncoherently without a carrier reference by using a simple envelope detector, as shown in Fig. 7.3c. Noncoherent reception provides a simpler implementation, but the output SNR of the noncoherent receiver is 3 dB lower than that of the coherent receiver. The bandwidth ef ciency of OOK depends on the chosen pulse shape p(t). For a rectangular pulse shape, if we de ne the transmission bandwidth as the bandwidth between the rst zero crossings of the spectrum, the bandwidth ef ciency is = Rb /W = 0.5. If ideal (sin x)/x pulses (having a rectangular spectrum) are used, the bandwidth ef ciency increases to = 1. Although this method of modulation is indeed very simple, use of the scheme poses some nontrivial problems in the design of the demodulator. For ef cient reception of the OOK signal in additive noise, the demodulator must set a detection threshold

To create a striped volume, you need to have at least two dynamic disks with unallocated disk space. Each area from each of these disks used by the striped volume will have the same size. You do not need to be concerned about this when creating the striped volume because Disk Management will ensure that all pieces are equally large it will simply allocate space on each disk using the size of the smallest unallocated space among all of them. However, keep this in mind when designing the layout of your volumes. Remember that boot or system volumes cannot be parts of a stripe. Evaluate your storage needs carefully, because striped volumes cannot be extended. Create a striped volume with the following steps: 1. In the Disk Management console, switch to Graphical View by selecting View Graphical View. Bottom

Display Method: Select the system used to display video and how much data DV Decoder: Select the quality of the video display. The higher the quality,

.\WPI\AK3F\tA0\rC\rc7_m1.s1p, (92.7ns, 104.7dB)

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