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To test the performance of this solution, run it against the BigNumSeq table:

To create the Parts and BOM tables and populate them with sample data, run the code in Listing 9-2. The contents of the Parts and BOM tables are shown in Tables 9-2 and 9-3.

SELECT seqval + 1 AS start_range, (SELECT MIN(B.seqval) FROM dbo.BigNumSeq AS B WHERE B.seqval > A.seqval) - 1 AS end_range FROM dbo.BigNumSeq AS A WHERE NOT EXISTS(SELECT * FROM dbo.BigNumSeq AS B WHERE B.seqval = A.seqval + 1) AND seqval < (SELECT MAX(seqval) FROM dbo.BigNumSeq);

SELECT DATEADD(day, DATEDIFF(day, '19000101', DATEADD(day, -1, SYSDATETIME())) /7*7 + 7, '19000101');

On my system, this solution ran for 8 seconds and incurred 62,262 logical reads. This is the fastest of all solutions I tested for the gaps problem. To understand why it performs so well (compared to others), examine this query s execution plan, which is shown in Figure 6-11.

The trick is to simply use the first day of the month calculation as the reference date within the next weekday occurrence calculation . For example, the following expression returns the first occurrence of a Monday in the reference month:

partid partname 1 2 3 4 5 6 7 8 9 10 11 12 13 14 Black Tea White Tea Latte Espresso Double Espresso Cup Cover Regular Cup Stirrer Espresso Cup Tea Shot Milk Coffee Shot Tea Leaves Water

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The key to the good performance of this solution is the way the optimizer decided to handle the point before a gap part represented in our query by the NOT EXISTS predicate. The optimizer identi ed this part logically as an anti-semi join and processed it with a merge join operator between two ordered scans of the index on seqval (one complete and another almost complete). These two scans incurred a little more than 32,000 reads, with the physical part probably being sequential. For almost 10,000,000 rows, this is far more ef cient than doing a seek operation per each row. Next, only for the ltered points identi ed as points before gaps, the optimizer uses an index seek operation to fetch the next sequence value. Because our sequence has close to 10,000 such points and 3 levels in the index, this activity amounts to about 30,000 reads, with the physical part being random. All in all, the number of logical reads is a little more than 62,000 reads. Note that the number of seek operations depends on the number of gaps in the sequence. Therefore, the performance of this solution varies based on the number of gaps. To apply this solution to a temporal sequence, instead of using + 1 or 1, simply use the DATEADD function with the appropriate interval, like so:

SELECT DATEADD(day, DATEDIFF(day, '19000101', -- first day of month DATEADD(month, DATEDIFF(month, '19000101', SYSDATETIME()), '19000101') -1) /7*7 + 7, '19000101');

SELECT DATEADD(hour, 4, seqval) AS start_range, DATEADD(hour, -4, (SELECT MIN(B.seqval) FROM dbo.TempSeq AS B WHERE B.seqval > A.seqval)) AS end_range

partid assemblyid unit qty 1 2 3 4 5 6 7 10 14 6 7 10 14 11 6 7 11 12 9 12 9 12 13 14 14 16 17 NULL NULL NULL NULL NULL 1 1 1 1 2 2 2 2 2 3 3 3 3 4 4 5 5 10 10 12 12 16 EA EA EA EA EA EA EA EA mL EA EA EA mL mL EA EA mL EA EA EA EA EA g mL mL g g 1.00 1.00 1.00 1.00 1.00 1.00 1.00 1.00 230.00 1.00 1.00 1.00 205.00 25.00 1.00 1.00 225.00 1.00 1.00 1.00 1.00 2.00 5.00 20.00 20.00 15.00 15.00

6

To handle a different weekday, replace the anchor date in the part of the expression that calculates the next occurrence of a weekday not in the part that calculates the first month day . The following expression returns the date of the first occurrence of a Tuesday in the reference month:

FROM dbo.TempSeq AS A WHERE NOT EXISTS(SELECT * FROM dbo.TempSeq AS B WHERE B.seqval = DATEADD(hour, 4, A.seqval)) AND seqval < (SELECT MAX(seqval) FROM dbo.TempSeq);

SELECT DATEADD(day, DATEDIFF(day, '19000102', -- first day of month DATEADD(month, DATEDIFF(month, '19000101', SYSDATETIME()), '19000101') -1) /7*7 + 7, '19000102');

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