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Notice that the first scenario (employee organizational chart) requires only one table because it is modeled as a tree; both an edge (manager, employee) and a vertex (employee) can be represented by the same row. The BOM scenario requires two tables because it is modeled as a DAG, where multiple paths can lead to each node; an edge (assembly, part) is represented by a row in the BOM table, and a vertex (part) is represented by a row in the Parts table.

You have a couple of options for dealing with a nonunique sequence. One is to replace the reference in the outer query to the original table with a reference to a derived table that has only distinct values, like so:

To calculate the date of the last occurrence of a weekday in the reference month you need to combine two calculations as well . One is the calculation of the last day of the reference month:

SELECT seqval + 1 AS start_range, (SELECT MIN(B.seqval) FROM dbo.NumSeqDups AS B WHERE B.seqval > A.seqval) - 1 AS end_range FROM (SELECT DISTINCT seqval FROM dbo.NumSeqDups) AS A WHERE NOT EXISTS(SELECT * FROM dbo.NumSeqDups AS B WHERE B.seqval = A.seqval + 1) AND seqval < (SELECT MAX(seqval) FROM dbo.NumSeqDups);

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SET NOCOUNT ON; USE tempdb; GO IF OBJECT_ID('dbo.BOM') IS NOT NULL DROP TABLE dbo.BOM; GO IF OBJECT_ID('dbo.Parts') IS NOT NULL DROP TABLE dbo.Parts; GO CREATE TABLE dbo.Parts ( partid INT NOT NULL PRIMARY KEY, partname VARCHAR(25) NOT NULL ); INSERT INSERT INSERT INSERT INSERT INSERT INSERT INSERT INSERT INSERT INSERT INSERT INSERT INSERT INSERT INSERT INSERT INTO INTO INTO INTO INTO INTO INTO INTO INTO INTO INTO INTO INTO INTO INTO INTO INTO dbo.Parts(partid, dbo.Parts(partid, dbo.Parts(partid, dbo.Parts(partid, dbo.Parts(partid, dbo.Parts(partid, dbo.Parts(partid, dbo.Parts(partid, dbo.Parts(partid, dbo.Parts(partid, dbo.Parts(partid, dbo.Parts(partid, dbo.Parts(partid, dbo.Parts(partid, dbo.Parts(partid, dbo.Parts(partid, dbo.Parts(partid, partname) partname) partname) partname) partname) partname) partname) partname) partname) partname) partname) partname) partname) partname) partname) partname) partname) VALUES( 1, VALUES( 2, VALUES( 3, VALUES( 4, VALUES( 5, VALUES( 6, VALUES( 7, VALUES( 8, VALUES( 9, VALUES(10, VALUES(11, VALUES(12, VALUES(13, VALUES(14, VALUES(15, VALUES(16, VALUES(17, 'Black Tea'); 'White Tea'); 'Latte'); 'Espresso'); 'Double Espresso'); 'Cup Cover'); 'Regular Cup'); 'Stirrer'); 'Espresso Cup'); 'Tea Shot'); 'Milk'); 'Coffee Shot'); 'Tea Leaves'); 'Water'); 'Sugar Bag'); 'Ground Coffee'); 'Coffee Beans');

Another is to simply use a DISTINCT clause in the SELECT list:

SELECT DATEADD(month, DATEDIFF(month, '18991231', SYSDATETIME()), '18991231');

SELECT DISTINCT seqval + 1 AS start_range, (SELECT MIN(B.seqval) FROM dbo.NumSeqDups AS B WHERE B.seqval > A.seqval) - 1 AS end_range FROM dbo.NumSeqDups AS A WHERE NOT EXISTS(SELECT * FROM dbo.NumSeqDups AS B WHERE B.seqval = A.seqval + 1) AND seqval < (SELECT MAX(seqval) FROM dbo.NumSeqDups);

The other is the calculation of the previous occurrence of a weekday, inclusive Monday in this example:

CREATE TABLE dbo.BOM ( partid INT NOT NULL REFERENCES dbo.Parts, assemblyid INT NULL REFERENCES dbo.Parts, unit VARCHAR(3) NOT NULL, qty DECIMAL(8, 2) NOT NULL, UNIQUE(partid, assemblyid), CHECK (partid <> assemblyid) ); INSERT INTO dbo.BOM(partid, assemblyid, unit, qty) VALUES( 1, NULL, 'EA', 1.00);

The second approach to solving the gaps problem is one I nd to be simpler and more intuitive than the previous. It implements the following steps: 1. To each existing value, match the next existing value, generating current, next pairs. 2. Keep only pairs where next minus current is greater than one interval. 3. With the remaining pairs, add one interval to the current and subtract one interval from the next. This approach relies on the fact that adjacent values with a difference greater than one interval represent the boundaries of a gap. Identifying a gap based on identi cation of the next existing value is another useful fundamental technique.

SELECT DATEADD(day, DATEDIFF(day, '19000101', SYSDATETIME()) /7*7, '19000101');

To translate the preceding steps to T-SQL, the following query simply returns the next value for each current value:

SELECT seqval AS cur, (SELECT MIN(B.seqval) FROM dbo.NumSeq AS B WHERE B.seqval > A.seqval) AS nxt FROM dbo.NumSeq AS A;

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