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void *operator new(size_t size); void operator delete(void *p); void *operator new[](size_t size); void operator delete[](void *p); }; // new overloaded relative to loc void *loc::operator new(size_t size) { void *p; cout << "In overloaded new\n"; p = malloc(size); if(!p) { bad_alloc ba; throw ba; } return p; } C++ // delete overloaded relative to loc void loc::operator delete(void *p) { cout << "In overloaded delete\n"; free(p); } // new overloaded for loc arrays void *loc::operator new[](size_t size) { void *p; cout << "Using overload new[]\n"; p = malloc(size); if(!p) { bad_alloc ba; throw ba; }

return p; } // delete overloaded for loc arrays void loc::operator delete[](void *p) { cout << "Freeing array using overloaded delete[]\n"; free(p); } int main() { loc *p1, *p2; int i; try { p1 = new loc (10, 20); // allocate an object } catch (bad_alloc xa) { cout << "Allocation error for p1\n"; return 1; } try { p2 = new loc [10]; // allocate an array } catch (bad_alloc xa) { cout << "Allocation error for p2\n"; return 1; } p1->show(); for(i=0; i<10; i++) p2[i]show(); delete p1; // free an object delete [] p2; // free an array return 0; }

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Art and music schools have been around for some time, of course, but we re now starting to see the emergence of trade schools dedicated to new media careers Few are

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Both function and data members of a class can be made static This section explains the consequences of each

The keyword static can be applied to members of a class Its meaning in this context is similar to its original C-like meaning When you declare a member of a class as static, you are telling the compiler that no matter how many objects of the class are created, there is only one copy of the static member A static member is shared by all objects of the class All static data is initialized to zero when the first object of its class is created and if no other initialization is specified When you declare a static data member within a class, you are not defining it (That is, you are not allocating storage for it) Instead, you must provide a global definition for it elsewhere, outside the class You do this by redeclaring the static variable, using the scope resolution operator to identify which class it belongs to This is necessary for storage to be allocated for the static variable To understand the usage and effect of a static data member, consider this program:

#include <iostream> using namespace std; class shared { static int a; int b; public: void set(int i, int j) { a=i; b=j; } void show(); } ; int shared::a; // define a void shared::show() { cout << "This is static a: " << a; cout << "\nThis is non-static b: " << b; cout << "\n"; } C++

Sizing the Anode(s)

int main() { shared x, y; xset(1, 1); // set a to 1 xshow(); yset(2, 2); // change a to 2 yshow(); xshow(); /* Here, a has been changed for both x and y because a is shared by both objects */ return 0; }

specifically intended for game developers and no one else (DigiPen in Washington state being a notable exception) Most cover such things as graphic design, multimedia, and programming for web sites as well Full Sail, in Florida, covers game development in addition to film and music industry techniques A number of traditional art colleges have added game art to their lineup as well Appendix A contains an extensive list

This This This This This This is is is is is is static a: 1 non-static b: 1 static a: 2 non-static b: 2 static a: 2 non-static b: 1

Notice that the integer a is declared both inside shared and outside of it As mentioned earlier, this is necessary because the declaration of a inside shared does not allocate storage As a convenience, older versions of C++ did not require the second declaration of a static member variable However, this convenience gave rise to serious inconsistencies, and it was eliminated several years ago Nonetheless, you may still find older C++ code that does not redeclare static member variables In these cases, you will need to add the required definitions

The memicmp( ) function is identical to memcmp( ) except that case is ignored when comparing letters

This program shows the outcome of a comparison of its two command line arguments:

#include <stdioh> #include <stringh> int main(int argc, char *argv[]) { int outcome; size_t len, l1, l2;

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