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Description Comparisons are performed using the currently active cultural settings Case-insensitive comparisons are performed using the currently active cultural settings Comparisons are performed using an invariant (that is, universal and unchanging) culture Case-insensitive comparisons are performed using an invariant (that is, universal and unchanging) culture Comparisons are performed using the ordinal values of the characters in the string Thus, dictionary-order may not result and cultural conventions are ignored Case-insensitive comparisons are performed using the ordinal values of the characters in the string Thus, dictionary-order may not result and cultural conventions are ignored

480 ________ 164(72)

TABLE 22-2

5 ) ln(43 )]

Part II:

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// Demonstrate string comparisons using System; class CompareDemo { static void Main() { string str1 = "alpha"; string str2 = "Alpha"; string str3 = "Beta"; string str4 = "alpha"; string str5 = "alpha, beta"; int result; // First, demonstrate the differences between culture-sensitive // and ordinal comparison result = StringCompare(str1, str2, StringComparisonCurrentCulture); ConsoleWrite("Using a culture-sensitive comparison: "); if(result < 0) ConsoleWriteLine(str1 + " is less than " + str2); else if(result > 0) ConsoleWriteLine(str1 + " is greater than " + str2); else ConsoleWriteLine(str1 + " equals " + str2); result = StringCompare(str1, str2, StringComparisonOrdinal); ConsoleWrite("Using an ordinal comparison: "); if(result < 0) ConsoleWriteLine(str1 + " is less than " + str2); else if(result > 0) ConsoleWriteLine(str1 + " is greater than " + str2); else ConsoleWriteLine(str1 + " equals " + str4); // Use the CompareOrdinal() method result = StringCompareOrdinal(str1, str2); ConsoleWrite("Using CompareOrdinal(): "); if(result < 0) ConsoleWriteLine(str1 + " is less than " + str2); else if(result > 0) ConsoleWriteLine(str1 + " is greater than " + str2); else ConsoleWriteLine(str1 + " equals " + str4); ConsoleWriteLine(); // Use == to determine if two strings are equal // This comparison is ordinal if(str1 == str4) ConsoleWriteLine(str1 + " == " + str4); // Use != on strings if(str1 != str3) ConsoleWriteLine(str1 + " != " + str3); if(str1 != str2) ConsoleWriteLine(str1 + " != " + str2);

22:

But now there is a problem: we cannot solve this equation uniquely for f 1 (t) 1 (t) = + t or f 1 (t) = t Thus f 1 is not We do not know whether f a well de ned function Therefore f is not invertible and f 1 does not exist Math Note: There is a simple device which often enables us to obtain an inverse even in situations like Example 142 We change the domain of the function This idea is illustrated in the next example EXAMPLE 143 De ne f : {s : s 0} {t : t 0} by the formula f (s) = s 2 Find f 1 SOLUTION We attempt to solve (f f 1 )(t) = t Writing this out, we have f (f 1 (t)) = t or [f 1 (t)]2 = t

ConsoleWriteLine(); // Use Equals() to perform an ordinal, case-insensitive comparison if(StringEquals(str1, str2, StringComparisonOrdinalIgnoreCase)) ConsoleWriteLine("Using Equals() with OrdinalIgnoreCase, " + str1 + " equals " + str2); ConsoleWriteLine(); // Compare a portion of a string if(StringCompare(str2, 0, str5, 0, 3, StringComparisonCurrentCulture) > 0) { ConsoleWriteLine("Using the current culture, the first " + "3 characters of " + str2 + "\nare greater than the first " + "3 characters of " + str5); } } }

rec MHz ______________

The output is shown here:

Using a culture-sensitive comparison: alpha is less than Alpha Using an ordinal comparison: alpha is greater than Alpha Using CompareOrdinal(): alpha is greater than Alpha alpha == alpha alpha != Beta alpha != Alpha Using Equals() with OrdinalIgnoreCase, alpha equals Alpha Using the current culture, the first 3 characters of Alpha are greater than the first 3 characters of alpha, beta

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