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Flyback PFC Transient.Cir .PROBE .TRAN 1U 20m 0 5u UIC .FOUR 60 I(V1) R2 vout 0 7.5 R3 3 32 1m L1B 2 32 100u V4 2 10 X1 10 6 0 IRFBC30 D2 1 11 40EPS08 V1 7 19 DC=163 SIN 0 163 60 C2 vout 13 2500u IC=28 C1 vout 14 2500u IC=28 V3 11 vout R4 13 0 20m R5 14 0 20m X4 8 19 3 0 KBPC808 X3 32 2 0 1 XFMR Params: RATIO=.15 C7 8 19 .47u L3 7 8 1m V9 5 0 PULSE 0 12 0 .01u .01u 4u 10u R10 5 6 4.7 .END

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A Boolean object can t be used like a boolean primitive. The three most important method families are xxxValue() Takes no arguments, returns a primitive parseXxx() Takes a String, returns a primitive, is static, throws NFE valueOf() Takes a String, returns a wrapped object, is static,

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jIA j jIB j jIC j IL Thus, comparison of eqs. (440) and (444) shows that PT is calculated the same way for either a Y-connected or a -connected load. In the above, be reminded that VL and IL are the rms values of line voltage and line current, and thus PT is the total average power produced in a balanced three-phase load. In section 10.7 we mentioned that the total INSTANTANEOUS POWER in a balanced three-phase system is constant. This interesting and important fact can be proved as follows. In Fig. 257, let va , vb , and vc denote the instantaneous values of the three sinusoidal line voltages; then, letting V 0 denote the three equal peak voltages, the instantaneous values of the three voltage waves are va V 0 sin !t vb V 0 sin !t 1208 * vc V 0 sin !t 2408 V 0 sin !t 1208 Then, since the above voltages work into identical loads, the corresponding instantaneous currents would be, letting I 0 denote the three equal peak currents, ia I 0 sin !t ib I 0 sin !t 1208 ic I 0 sin !t 1208 where is the phase angle between the voltage and current waves. Then the total INSTANTANEOUS POWER p is equal to p va ia vb ib vc ic which, upon making the above substitutions, becomes p V 0 I 0 sin !t sin !t sin !t 1208 sin !t 1208 sin !t 1208 sin !t 1208 Note that the above result seemingly says that p is a function of time t, that is, that p varies from instant-to-instant, thus contradicting the statement we made that p remains

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Radix refers to bases (typically) other than 10; binary is radix 2, octal = 8,

Using equals() (Exam Objective 5.2) Use == to compare primitive variables. Use == to determine if two reference variables refer to the same object. == compares bit patterns, either primitive bits or reference bits. Use equals() to determine if two objects are meaningfully equivalent. The String and Wrapper classes override equals() to check for values. The StringBuffer class equals() is not overridden; it uses == under

* Since it s always understood that !t 2 ft radians, it s basically incorrect to write sin !t 1208); instead, since 1208 120 =180 2 =3 rad., we should really write sin !t 2 =3 . However, the particular operation above is such that there is no harm in writing 1208 instead of 2 =3 radians if we wish to do so.

The compiler will not allow == if the classes are not in the same hierarchy. Wrappers won t pass equals() if they are in different classes.

Discontinuous Flyback Power Factor Corrector The discontinuous yback converter is the simplest topology that can be used to provide power factor correction. The peak input current of the discontinuous yback converter, with a xed duty cycle and xed

The following questions will help you measure your understanding of the material presented in this chapter. Read all of the choices carefully, as there may be more than one correct answer. Choose all correct answers for each question.

constant, independent of time. If, however, you have the patience to carefully apply the following trigonometrical identities sin x sin y 1 cos x y cos x y 2 and cos x y cos x cos y sin x sin y note 6 in Appendix note 25 in Appendix

Using the java.lang.String Class (Exam Objective 8.2)

1. Given the following,

to the foregoing equation for p, you ll nd that the expression actually reduces to p 1:5V 0 I 0 cos 445

1. 2. 3. 4. 5. 6. 7. 8. 9. public class StringRef { public static void main(String [] args) { String s1 = "abc"; String s2 = "def"; String s3 = s2; s2 = "ghi"; System.out.println(s1 + s2 + s3); } }

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