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This is a fairly odd operator. For this example, I need a source sequence of nodes. Since I want to see some nodes that are not elements in addition to elements, I will build a sequence of nodes that are the child nodes of the BookParticipant elements. I do this because one of them has a comment, which is a node, but not an element. My source is shown in Listing 8-17. Listing 8-17. Calling the Only InDocumentOrder Prototype XDocument xDocument = new XDocument( new XElement("BookParticipants", new XElement("BookParticipant", new XAttribute("type", "Author"), new XComment("This is a new author."), new XElement("FirstName", "Joe"), new XElement("LastName", "Rattz")), new XElement("BookParticipant", new XAttribute("type", "Editor"), new XElement("FirstName", "Ewan"), new XElement("LastName", "Buckingham"))));

In 5, I will cover the integration tier patterns. You have already had a short glimpse of an integration tier pattern: the Data Access Object pattern. Integration tier patterns expose a variety of strategies to retrieve data for use by the business components. These patterns also help business objects alter enterprise data. In addition to this, I will explore strategies to expose business tier functionalities for use by external clients.

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IEnumerable<XNode> nodes = xDocument.Element("BookParticipants").Elements("BookParticipant"). Nodes().Reverse(); // First, I will display the source nodes. foreach (XNode node in nodes) { Console.WriteLine("Source node: {0}", node); } // Now, I will display each source node's child nodes. foreach (XNode node in nodes.InDocumentOrder()) { Console.WriteLine("Ordered node: {0}", node); } As you can see in the previous code, I build my XML tree. When I retrieve my source sequence, I get the BookParticipant element s child nodes by calling the Nodes operator, and then I call the Reverse Standard Query Operator. If you recall from Part 2 of this book about LINQ to Objects, the Reverse operator will return a sequence where entries in the input sequence have had their order reversed. So now I have a sequence of nodes that are not in the original order. I take this additional step of altering the order so that when I call the InDocumentOrder operator, a difference can be detected. Then I display the disordered source nodes, call the InDocumentOrder operator, and display the results. Here they are: Source node: <LastName>Buckingham</LastName> Source node: <FirstName>Ewan</FirstName> Source node: <LastName>Rattz</LastName> Source node: <FirstName>Joe</FirstName> Source node: <!--This is a new author.--> Ordered node: <!--This is a new author.--> Ordered node: <FirstName>Joe</FirstName> Ordered node: <LastName>Rattz</LastName> Ordered node: <FirstName>Ewan</FirstName> Ordered node: <LastName>Buckingham</LastName> As you can see, the source nodes are in the reverse order that I built them in, and the ordered nodes are back in the original order. Cool, but odd.

The Nodes operator can be called on a sequence of elements or documents and returns a sequence of nodes containing each source element s or document s child nodes. This operator is different than the DescendantNodes operator in that the Nodes operator only returns the immediate child elements of each element in the source sequence of elements, whereas the DescendantNodes operator recursively returns all child nodes until the end of each tree is reached.

Figure 5-3. Sample form-filling dialog call flow As you can see from the call flow in Figure 5-3, the design is for a form-filling dialog, with three questions. Listing 5-1 shows the code for this application. Listing 5-1. Sample VoiceXML Application <var name="productName" /> <var name="productColor" /> <var name="productSize" />

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