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To check a password, Ray has to mix the salt and password the same way Pao-Chi did. Pao-Chi can slow Ray down by making that a lengthy task. His goal will be to make the process quick enough that it doesn t make his own encryption or decryption process too expensive, but slow enough to be a drain on Ray. He can do this by repeating the mixing over and over. First, mix the salt and password together. Then take the result of that and run it through the blender again. Then take the result of that and run it through the blender. And on and on, say 1,000 times. The blender is probably pretty fast, the mixing is almost certainly done with a message digest, and these algorithms are generally very fast, so for Pao-Chi to do 1,000 iterations of the mixing process won t be too time-consuming. In fact entering a password is going to be far more timeconsuming than 1,000 mixings. So relatively speaking, for Pao-Chi, the mixing takes up a very small portion of the total time. But Ray is going to have to do 1,000 mixings for every password he tries. That can add up. Let s say Pao-Chi has an eight-character password. In an earlier section we said that an eight-character password is equivalent to a 52-bit key. But actually, Ray cannot try one password as quickly as one key. If he tries the brute-force attack on a key, here s the process (BFK stands for brute-force on the key ): BFK1 BFK2 BFK3 BFK4 Get a candidate key. Do key setup (recall the key table from 2). Decrypt some ciphertext, yielding some purported plaintext. Check the plaintext.

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*rSense({ExprN}) Returns a number 0 to 7 according to the following logic: There are three sensors around the robot, at 10 to the left and right of the robot and directly in the front The sensors see only the color speci ed by ExprN or, if you don t specify ExprN, then the rst color on the invisible colors list If neither is speci ed then the oor color will be sensed The sensors only look at the ground directly under the sensor situated directly at the perimeter of the robot The number returned is a bitmap of the condition of the sensors If any of the sensors sees the ExprN color then its bit position is set to 1, otherwise it is 0 There are 3 bits MSBLSB 000.

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But for each password Ray checks, on the other hand, here s the process (BFP stands for brute-force on the password ): BFP1 BFP2 BFP3 Get a candidate password. Perform the mixing to build the candidate key. Do key setup.

The most signi cant bit is the sensor 10 to the left, then ahead (0 ) and then 10 to the right If the number is 010 (2) then only the sensor in the front is on the line and the other two are outside of the line Use bitwise operators (bAND, bOR, etc) to manipulate the result rGround(ExprN ) The robot has a default of three sensors to look at the ground directly at the perimeter of the robot ExprN1 speci es the sensor number 1 = 10 to the right 2 = In front 3 = 10 to the left It will return the color seen by the sensor It will not ignore any color (ie, the colors on the invisible colors list are not ignored) It is up to you what to make of the value.

How long it takes to do one BFK depends on four things How long it takes to do one BFP depends on those same four things, plus one more If step BFP2 is as long as the other four steps combined, that s going to double the amount of time to check one password That s like adding one bit to your password The eight-character password which was equivalent to a 52-bit key is now more like a 53-bit key In our experiments, performing 1,000 iterations (doing step BFP2 1,000 times) is about 136 times slower than the other steps combined (more or less, depending on the encryption algorithm; we used RC4, a very fast algorithm) On one Pentium-based PC, step BFP2 took 436 milliseconds, whereas checking one key took 0.

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